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[转]C++对象内存分配
阅读量:7055 次
发布时间:2019-06-28

本文共 7156 字,大约阅读时间需要 23 分钟。

很久以前收藏的原文地址找不到了。

单继承对象内存分配:

#include 
using namespace std;class Base1{public: long ibase1; int ibase12; Base1():ibase1(10),ibase12(100) {} virtual void f() { cout << "Base1::f()" << endl; } virtual void g() { cout << "Base1::g()" << endl; } virtual void h() { cout << "Base1::h()" << endl; }};class Base2{public: int ibase2; long ibasee21; Base2():ibase2(20),ibasee21(21) {} virtual void f() { cout << "Base2::f()" << endl; } virtual void g() { cout << "Base2::g()" << endl; } virtual void h() { cout << "Base2::h()" << endl; }};class Base3{public: int ibase3; Base3():ibase3(30) {} virtual void f() { cout << "Base3::f()" << endl; } virtual void g() { cout << "Base3::g()" << endl; } virtual void h() { cout << "Base3::h()" << endl; }};class Derive : public Base1, public Base2, public Base3{public: int iderive; Derive():iderive(100) {} virtual void f() { cout << "Derive::f()" << endl; } virtual void g1() { cout << "Derive::g1()" << endl; }};typedef void(*Fun)(void);Fun pFun;int main(){ Derive d; int** pVtab = (int**)&d; cout << "[0] Base1::_vptr->" << endl; pFun = (Fun)pVtab[0][0]; cout << " [0] "; pFun(); pFun = (Fun)pVtab[0][1]; cout << " [1] "; pFun(); pFun = (Fun)pVtab[0][2]; cout << " [2] "; pFun(); pFun = (Fun)pVtab[0][3]; cout << " [3] "; pFun(); pFun = (Fun)pVtab[0][4]; cout << " [4] "; cout<
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重复继承内存分配:

 

#include 
using namespace std;class B{ public: int ib; char cb; public: B():ib(0),cb('B') {} virtual void f() { cout << "B::f()" << endl;} virtual void Bf() { cout << "B::Bf()" << endl;}};class B1 : public B{ public: int ib1; char cb1; public: B1():ib1(11),cb1('1') {} virtual void f() { cout << "B1::f()" << endl;} virtual void f1() { cout << "B1::f1()" << endl;} virtual void Bf1() { cout << "B1::Bf1()" << endl;};class B2: public B{ public: int ib2; char cb2; public: B2():ib2(12),cb2('2') {} virtual void f() { cout << "B2::f()" << endl;} virtual void f2() { cout << "B2::f2()" << endl;} virtual void Bf2() { cout << "B2::Bf2()" << endl;}};class D : public B1, public B2{ public: int id; char cd; public: D():id(100),cd('D') {} virtual void f() { cout << "D::f()" << endl;} virtual void f1() { cout << "D::f1()" << endl;} virtual void f2() { cout << "D::f2()" << endl;} virtual void Df() { cout << "D::Df()" << endl;}}; typedef void(*Fun)(void); int** pVtab = NULL; Fun pFun = NULL;int main(){ D d; pVtab = (int**)&d; cout << "[0] D::B1::_vptr->" << endl; pFun = (Fun)pVtab[0][0]; cout << " [0] "; pFun(); pFun = (Fun)pVtab[0][1]; cout << " [1] "; pFun(); pFun = (Fun)pVtab[0][2]; cout << " [2] "; pFun(); pFun = (Fun)pVtab[0][3]; cout << " [3] "; pFun(); pFun = (Fun)pVtab[0][4]; cout << " [4] "; pFun(); pFun = (Fun)pVtab[0][5]; cout << " [5] 0x" << pFun << endl; cout << "[1] B::ib = " << (int)pVtab[1] << endl; cout << "[2] B::cb = " << (char)pVtab[2] << endl; cout << "[3] B1::ib1 = " << (int)pVtab[3] << endl; cout << "[4] B1::cb1 = " << (char)pVtab[4] << endl; cout << "[5] D::B2::_vptr->" << endl; pFun = (Fun)pVtab[5][0]; cout << " [0] "; pFun(); pFun = (Fun)pVtab[5][1]; cout << " [1] "; pFun(); pFun = (Fun)pVtab[5][2]; cout << " [2] "; pFun(); pFun = (Fun)pVtab[5][3]; cout << " [3] "; pFun(); pFun = (Fun)pVtab[5][4]; cout << " [4] 0x" << pFun << endl; cout << "[6] B::ib = " << (int)pVtab[6] << endl; cout << "[7] B::cb = " << (char)pVtab[7] << endl; cout << "[8] B2::ib2 = " << (int)pVtab[8] << endl; cout << "[9] B2::cb2 = " << (char)pVtab[9] << endl; cout << "[10] D::id = " << (int)pVtab[10] << endl; cout << "[11] D::cd = " << (char)pVtab[11] << endl;}

我们可以看见,最顶端的父类B其成员变量存在于B1和B2中,并被D给继承下去了。而在D中,其有B1和B2的实例,于是B的成员在D的实例中存在两份,一份是B1继承而来的,另一份是B2继承而来的。所以,如果我们使用以下语句,则会产生二义性编译错误:

 

D d;

d.ib = 0;               //二义性错误

d.B1::ib = 1;           //正确

d.B2::ib = 2;           //正确

 

注意,上面例程中的最后两条语句存取的是两个变量。虽然我们消除了二义性的编译错误,但B类在D中还是有两个实例,这种继承造成了数据的重复,我们叫这种继承为重复继承。重复的基类数据成员可能并不是我们想要的。所以,C++引入了虚基类的概念。

 钻石型多重虚拟继承内存分配:

#include 
using namespace std;class B{public: int ib; char cb;public: B():ib(0),cb('B') {} virtual void f() { cout << "B::f()" << endl; } virtual void Bf() { cout << "B::Bf()" << endl; }};class B1 : virtual public B//虚拟继承{public: int ib1; char cb1;public: B1():ib1(11),cb1('1') {} virtual void f() { cout << "B1::f()" << endl; } virtual void f1() { cout << "B1::f1()" << endl; } virtual void Bf1() { cout << "B1::Bf1()" << endl; }};class B2: virtual public B//虚拟继承{public: int ib2; char cb2;public: B2():ib2(12),cb2('2') {} virtual void f()   { cout << "B2::f()" << endl; } virtual void f2() { cout << "B2::f2()" << endl; } virtual void Bf2() { cout << "B2::Bf2()" << endl; }};class D : public B1, public B2{public: int id; char cd;public: D():id(100),cd('D') {} virtual void f() { cout << "D::f()" << endl; } virtual void f1() { cout << "D::f1()" << endl; } virtual void f2() { cout << "D::f2()" << endl; } virtual void Df() { cout << "D::Df()" << endl; }};typedef void(*Fun)(void);int** pVtab = NULL;Fun pFun = NULL;int main(){ D dd; pVtab = (int**)ⅆ cout << "[0] D::B1::_vptr->" << endl; pFun = (Fun)pVtab[0][0]; cout << " [0] "; pFun(); //D::f1(); pFun = (Fun)pVtab[0][1]; cout << " [1] "; pFun(); //B1::Bf1(); pFun = (Fun)pVtab[0][2]; cout << " [2] "; pFun(); //D::Df(); pFun = (Fun)pVtab[0][3]; cout << " [3] "; cout << pFun << endl; //cout << pVtab[4][2] << endl; cout << "[1] = 0x"; cout << (int*)((&dd)+1) <
" << endl; pFun = (Fun)pVtab[4][0]; cout << " [0] "; pFun(); //D::f2(); pFun = (Fun)pVtab[4][1]; cout << " [1] "; pFun(); //B2::Bf2(); pFun = (Fun)pVtab[4][2]; cout << " [2] "; cout << pFun << endl; cout << "[5] = 0x"; cout << *((int*)(&dd)+5) << endl; // ??? cout << "[6] B2::ib2 = "; cout << (int)*((int*)(&dd)+6) <
" << endl; pFun = (Fun)pVtab[11][0]; cout << " [0] "; pFun(); //D::f(); pFun = (Fun)pVtab[11][1]; cout << " [1] "; pFun(); //B::Bf(); pFun = (Fun)pVtab[11][2]; cout << " [2] "; cout << pFun << endl; cout << "[12] B::ib = "; cout << *((int*)(&dd)+12) << endl; //B::ib cout << "[13] B::cb = "; cout << (char)*((int*)(&dd)+13) <

 

转载于:https://www.cnblogs.com/zhanjindong/articles/2833044.html

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